Calculating power for the FOOOF peaks of the periodic components

[Kshitij]

Certainly! Here’s a more formal version of your request:

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Hello,

I have extracted the FOOOF parameters related to the peaks, which include Amplitude, Standard Deviation, and Center Frequency. My objective is to compute the power at the Center Frequency.

I am uncertain whether either of the following approaches would yield the correct power calculation:

1. Power = AmplitudeStandard Deviationsqrt{2*pi}
2. Power = Amplitude

Given that the graph is in log-power, I am unsure how this affects the computation. Could someone provide clarification on the correct method for calculating power?

Thank you!

[Raymundo.Cassani]

FOOOF parameters are for the parametrization of the PSD, in this sense Amplitude refers to amplitude in the PSD so, it's really power, and it is given in Bells [B]. See this link for a description of FOOOF parameters:

https://neuroimage.usc.edu/brainstorm/Tutorials/Fooof#Accessing_FOOOF_model_parameters

Moreover, this other thread is relevant for your question:

FOOOF model, and PSD units

However, I have another related question and hope you could guide me. What is the formula for FOOOF? I have , for example, these parameters: aperiodic_params: [-9.18, 1.02] peak_params:[8.91, 1.69, 1.14; 18.35, 0.80, 1.40] Is the fitted function like this: 10^(-9.18) * f^(1.02) + 1.69exp(-1/2((f-8.91)/1.14)^2 ) + 0.80exp(-1/2((f-18.35)/1.40)^2 ) or something else? In addition, I have particularly problem with the units of PSD. Please look at these three plots of the same PSDs: The FOOOF p…

[Kshitij]

I read that @Raymundo.Cassani ! sorry for the confusion, so i just have to multiply the amplitude with 10 and it will give me the power in logpower ! please correct me if wrong.

[Raymundo.Cassani]

No, FOOOF amplitude is already in Bell that is log10(power)

FOOOF_amplitude = log10(power)